# Learn How to Apply Full Scale Accuracy Measurement

## Full Scale Accuracy Measurement Tutorial

##### Definition:

Preciseness of an object is based on the percentage of its overall reading capability, then the error is considered as the fixed value. It is also termed as full precision, which denotes the level to which a device will deliver repeated measurement over a period. Let us find the full scale accuracy measurement on basic math operations listed.

##### Example:

Let us consider x as '5' and y as '2'. How to accumulate these two values? Substitute the values using the formula, (x+y)

x + y
5 + 2
7
##### 2] Subtraction:

Apply X as 5 and Y as 2. Learn to deduct these two values. Substitute the values using the formula, (x-y)

x - y
5 - 2
3
##### 3] Multiplication:

Let 'X' be 5 and 'Y' be 2. How to multiply these two values? Substitute the values using the formula, (x*y)

x * y
5 * 2
10
##### 4] Division:

Apply x as 5 and y as 2. Learn to do division for these values. To substitute the values use this formula (x/y)

x / y
5 / 2
2.5
##### 5] Modulo Division:

Assume 'x' as 5 and 'y' as 2. Full scale accuracy can be measured by, Substitute the values by using this formula (x%y)

x % y
5 % 2
1
##### 6] Factorial:

Let us consider X as 5. Now perform factorial for X. Apply and substitute the values using this formula (x!)

x!
5!
###### Step 3:
Factorial measurement is '120'.
##### 7] Square Root:

Consider X as 5. How to find the square root for X? Substitute the values using this formula (√x)

√x
√5
###### Step 3:
Square root of 5 is '2.2361'
##### 8] Power:

Apply X as 5 and Y as 2. Learn to find the power of X and Y. Substitute the values using this formula (xy)

xy
52
5*5 = 25