Gay-Lussac's Law states that the pressure of a fixed amount of gas at fixed volume is directly proportional to its temperature in kelvins.
Case 1: A cylinder contain a gas which has a pressure of 125kPa at a temperature of 200 K. Find the temperature of the gas which has a pressure of 100 kPa.
Pi = 125 kPa, Ti = 200 K, Pf = 100 kPa
Substitute the values in the below final temperature equation: Final Temperature(Tf) = PfTi / Pi = (100 x 200) / 100 = 20000 / 125 Final Temperature(Tf) = 160 K This example will guide you to calculate the final temperature manually. Case 2: Find the final pressure of gas at 150 K, if the pressure of gas is 210 kPa at 120 K. Pi = 210 kPa, Ti = 120 K, Tf = 150 K
Substitute the values in the below pressure equation:Final Pressure(Pf) = PiTf / Ti = (210 x 150) / 120 = 31500 / 120 Final Pressure(Vf) = 262.5 kPa This example will guide you to calculate the pressure manually.
This tutorial will help you dynamically to find the Gay-Lussac's Law problems.