A quadratic equation is a polynomial equation of the second degree. The general form is ax2+bx+c=0, where a ≠0.
Calculate the roots(x1, x2) of the quadratic equation, x2 + 2x - 8 = 0.
From the above equation, the value of a = 1, b = 2 and c = - 8.
To Find X: Substitute the values in the formula below x = (- b ±√ b2 - 4 * a * c) / 2 * a
We get the roots, x = (- 2 ±√ 22 - 4 * 1 * - 8) / 2 * 1 x = - 4 and x = 2 which means x1 = - 4 and x2 = 2.
Calculate the roots(x1, x2) of the quadratic equation, x2 - 10x + 25 = 0
From the above equation, the value of a = 1, b = - 10 and c = 25.
To Find X: Substitute the values in the formula below x = (- b ±√ b2 - 4 * a * c) / 2 * a
We get the roots, x = (- 2 ±√ 22 - 4 * 1 * - 8) / 2 * 1 x = 5 and x = 5 which means x1 = 5 and x2 = 5. Here x = 5 is called the double root. A quadratic will have a double root if the quadratic is a perfect square trinomial.
This tutorial will help you dynamically to find the roots of a quadratic equation.