Angle between two lines is an angle formed when two straight lines intersect each other.
Calculate the angle between the following lines where the values are represented in Cartesian Form (x + 1) / 2 = (y + 1) / 3 = (z - 4) / 6 => u1 = 2, u2 = 3, u3 = 6 (x + 1) = (y + 2) / 2 = (z - 4) / 2 => v1 = 1, v2 = 2, v3 = 2
In the given values the vector values are retrieved as follows: (u1,u2,u3) = (2,3,6) (v1,v2,v3) = (1,2,2)
Substitute the vector values in the formula,
cos α | = |((2 x 1) + (3 x 2) + (6 x 2))| / √22 + 32 + 62 . √12 + 22 + 22 |
= |(2 + 6 + 12)| / √49 . √9 | |
= |20| / (7 x 3) | |
= 20 / 21 | |
α | = cos-1 (0.9524) |
α | = 17.75o |
Therefore, the angle between 2 lines is 17.75
Calculate the angle between the following lines where the values are represented in Equation Form r = 2x + 3y - z = 0, x - y + 2z = 0 s = 3x - y + z = 0, 2x + y - 3z = 0
u = i [(3 x 2) - (-1 x -1)] - j [(2 x 2) - (-1 x 1)] + k [(2 x -1) - (3 x 1)] u = i(6 - 1) - j(4 + 1) + k(-2 - 3) u = 5i - 5j - 5k u = (5,-5,-5)
v = i [(-1 x -3) - (1 x 1)] - j [(-3 x 3) - (2 x 1)] + k [(3 x 1) - (2 x -1)] v = i(3 - 1) - j(-9 - 2) + k(3 + 2) v = 2i + 11j + 5k v = (2,11,5)
cos α | = |((5 x 2) + (-5 x 11) + (-5 x 5))| / √52 + (-5)2 + (-5)2 . √22 + 112 + 52 |
= |10 - 55 - 25| / √75 . √150 | |
= |-70| / 106.066 | |
= 70 / 106.066 | |
= 0.6599 | |
α | = cos-1(0.6599) |
α | = 48.7o |
Therefore, the angle between 2 lines is 48.7