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Cyclic Quadrilateral Ptolemy's Theorem Proof
The Theorem states that the product of the diagonals of a cyclic quadrilateral is equal to the sum of the products of opposite sides.
Cyclic Quadrilateral Ptolemy's Theorem
Given
A cyclic quadrilateral ABCD, with a,b,c,d as the length of the sides and e,f as the diagonals. Then,
ac+bd = ef
The binomial coefficient (r,c)=0 if c > r.
Proof:
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Given that a cyclic quadrilateral ABCD, extend CD to P such that |  |
Since quadilateral ABCD is cyclic,
However, is also supplementary to, ,
so
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Hence |  | by AA similarity, and |  |
Now, (subtend the same arc) and ,so 
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This yields |  |
However,CP=CD+DP.Substituting in our expressions for CP and DP 
Multiplying by AB yields 
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