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Gay-Lussac's Law Tutorial

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Gay-Lussac's Law:
     Gay-Lussac's Law states that the pressure of a fixed amount of gas at fixed volume is directly proportional to its temperature in kelvins.

Gay-Lussac's Law Formula :
Gas Equation: Pi/Ti = Pf / Tf
Initial Pressure(Pi) = PfTi / Tf
Initial Temperature(Ti) = PiTf / Pf
Final Pressure(Pf) = PiTf / Ti
Final Temperature(Tf) = PfTi / Pi
where,
Pi = Initial Pressure,
Ti = Initial Temperature,
Pf = Final Pressure. Tf = Final Temperature,

Gay-Lussac's Law Example:
Case 1: A cylinder contain a gas which has a pressure of 125kPa at a temperature of 200 K. Find the temperature of the gas which has a pressure of 100 kPa.
 Pi = 125 kPa, Ti = 200 K, Pf = 100 kPa
  Step 1: Substitute the values in the below final temperature equation:
            Final Temperature(Tf) = PfTi / Pi
            = (100 x 200) / 100
            = 20000 / 125
            Final Temperature(Tf) = 160 K
This example will guide you to calculate the final temperature manually.

Case 2: Find the final pressure of gas at 150 K, if the pressure of gas is 210 kPa at 120 K.
 Pi = 210 kPa, Ti = 120 K, Tf = 150 K
  Step 1: Substitute the values in the below pressure equation:
            Final Pressure(Pf) = PiTf / Ti
            = (210 x 150) / 120
            = 31500 / 120
            Final Pressure(Vf) = 262.5 kPa
This example will guide you to calculate the pressure manually.




This tutorial will help you dynamically to find the Gay-Lussac's Law problems.